4x^2+80x-4500=0

Solution for 4x^2+80x-4500=0 equation:

4x^2+80x-4500=0

a = 4; b = 80; c = -4500;
Δ = b2-4ac
Δ = 802-4·4·(-4500)
Δ = 78400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{78400}=280$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(80)-280}{2*4}=\frac{-360}{8}
=-45
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(80)+280}{2*4}=\frac{200}{8}
=25
$